2x^2+36x=-90

Solution for 2x^2+36x=-90 equation:

2x^2+36x=-90

We move all terms to the left:

2x^2+36x-(-90)=0

We add all the numbers together, and all the variables

2x^2+36x+90=0

a = 2; b = 36; c = +90;
Δ = b2-4ac
Δ = 362-4·2·90
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-24}{2*2}=\frac{-60}{4}
=-15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+24}{2*2}=\frac{-12}{4}
=-3
$